ECE3050 Homework Set 71. For the CE amplifier sho wn, let RS=1kΩ, R1=300kΩ, R2= 150 kΩ, R3=50Ω, RC=4.3kΩ, RE=5.6kΩ, RL=20kΩ, V+=15V, V−= −15 V, VBE=0.65 V, β =99,rx=20Ω, r0=50kΩ,andVT=25mV.(a) Show that IE=1.417 mA and VCB=15.386 V.(b) Use the r0approximations to show that vo/vs= −43.74, rout=4.169 kΩ,andrin=6.315 kΩ.(c) Show that the clipping levels are v+O=4.964 V and v−O= −15.62 V.(d) Show that the emitter current which results in symmetrical clipping is IE=2.222 mA.(e) Show that the clipping levels for IE=2.222 mA are v+O= −v−O=7.786 V.2. For the CC amplifier example shown, let Rs=1kΩ, R1= 300 kΩ, R2= 150 kΩ, RE=5.6kΩ,RL=1kΩ, V+=15V, V−= −15 V, VBE=0.65 V, β =99, rx=20Ω, r0=50kΩ,VCEsat=0.2V,andVT=25mV. In the ac signal circuit, combine r0in parallel with REfrom the emitter to ground. This can be done because Rtc=0, which puts r0in parallel withRE.(a) Show that IE=1.417 mA, VCB=21.417 V.(b) Show that vo/vs=0.958, rout=27.596 Ω,andrin=46.01 kΩ.(c) Show that the clipping levels are v+O=3.31 V and v−O= −1.20 V.(d) Show that the emitter current which results in symmetrical clipping is IE=2.661 mA.(e) Show that the clipping levels for IE=2.661 mA are v+O= −v−O=2.257 V.13. For the CB amplifier shown, let Rs=50Ω, R1= 300 kΩ, R2= 150 kΩ, RC=4.3kΩ,RE=5.6kΩ, RL=20kΩ, V+=15V, V−= −15 V, VBE=0.65 V, β =99, rx=20Ω,r0=50kΩ,andVT=25mV.(a) Show that IE=1.417 mA and VCB=15.386 V.(b) Use the r0approximations to show that vo/vs=50.552, rout=4.202 kΩ,andrin=17.79
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