STAT303 Secs 507-510Spring 2012Exam #1Form AInstructor: Julie Hagen CarrollMay 2, 20121. Do not open this exam until you are told to do so.2. There are 20 multiple-choice questions on this exam, each worth the same amount. Please mark your answers clearlyon a GRAY Scantron sheet. Multiple marks will be counted wrong.3. You must mark your Scantron form with(a) Your NAME and UIN.(b) Your correct SECTION (Thursday 11:10 is 507, 12:45 is 508, 2:20 is 509, and 3:55 is 510).(c) This test FORM (A, B, C, or D).(d) Your Form letter which is above.4. You will have only 50 minutes to finish this exam.5. You may use the following:(a) One 812× 11 formula sheet (both sides) of your own making.(b) A copy of the Percent Curve handout.(c) A copy of the Z tables.(d) A copy of the recap of Week 1 & 2.(e) A stand-alone calculator, i.e., one that cannot communicate with the internet or anything outside itself.6. You must put all possessions beside s , the materials listed and your scantron, pencil(s) and erase r , along the walls or atthe front of the room out of everyone else’s way. This includes cell phones, which must be turned off.7. If you have questions, please write out what you are thinking on this test so that we can discuss it after your results arereturned to you.8. If you are caught cheating or helping someone to cheat on this exam, you both will receive a grade of zero on the exam.You must work alone.9. When you are finished please make sure you have marked your Section and Form and have an answer for every question,then turn in your scantron and show your ID.10. Good luck!1STAT303 sec 507-510 Exam #1, Form A Spring 20121. If X ∼ N(30, 62), how likely are you to get an observationabove 35?A. 0.8333B. 0.1667C. 0.97D. 0.7987E. 0.20332. Which of the following is true about these boxplots?A. They have the same distribution.B. They have the same 5-Number Summary.C. They have the same mean and standard deviation.D. All of the above are correct.E. Only two of the above are c orrect.3. If we took samples of size 20 from a population of normaldata with mean µ = 8 and standar d deviation σ = 3, thedistribution of the sample means wouldA. be normal with mean µ = 8 and standard deviationσ = 3.B. be normal with mean µ = 8 and standard deviationσ = 3/√20.C. be normal with mean µ = 8/√20 and standard de-viation σ = 3/√20.D. have a mean µ = 8 and standard deviation σ =3/√20 but not be quite normal since n is only 20.E. have a mean µ = 8 and standard deviation σ = 3but not be quite normal since n is only 20.4. Jamie and Jo are both in a first semester statistics course,however, Jamie is taking it a Easy U and Jo is at A&M.Jamie made an 80 on the first exam and Jo only got a 75.The mean at Easy U was 82 with s = 1.25 and at A&M itwas 78 and 2. Who actually had the best performance?A. Jamie since 80 is bette r t h an 75.B. JamieC. JoD. Neither, since both made below average.E. The did relatively the same.5. Which of the following is/are true?A. Normal quantile plots are the only plots in whichwe can always determine if a distribution is approx-imately normal.B. Boxplots are the only plots in which we can alwaysdetermine if there are outliers.C. Stemplots are the only plots in which we can alwayscalculate the mean.D. All of the above are true.E. Only two of the above are true.6. The 5-Number Summary for ankle len gth is: 0.5, 7, 9,10, 20. Which of the following best describes this distri-bution?A. The shape is approximately symmetric and thereare 2 outliers.B. The shape is appr oximately normal and there is atleast 1 outlier on each end (min and max).C. The shape must be normal since there is at least 1outlier on each end (min and max).D. The shape is skewed right since 20 is further from 9than 0.5 is, i.e., it’s not symmetric.E. There must be an er r or since no one c ould have anankle circumference of a half inch.7. If we have a distr ib ut ion with a mean of 60 and a stan-dard deviation of 8, approximately what proportion ofthe observations will fall between 44 and 68?A. 68%B. 81.5%C. 95%D. 70.5%E. We can’t determine it.8. Whatcan we say about the distribution above?A. min is 5, Q1is 15, ˜x is 20, Q3is 20, max is 25B. min is 5 or 6, Q1is 15 or 16, ˜x is 20 or 21, Q3is 21or 22, max is 25 or 26C. min is 5, Q1is 15, ˜x is 20, Q3is 21, max is 25D. min is 5-7.5, Q1is 15-17.5, ˜x is 20-22.5, Q3is 20-22.5, max is 25-27.5E. We need the actual values to determine these num-bers.2STAT303 sec 507-510 Exam #1, Form A Spring 20129. Referring to the pre v ious histogram, what would be trueif the minimum value was 0, i.e., at least 5 was subtractedfrom the minimum only?A. The mean and standard deviation would be 5 less.B. The me an and standard dev iati on would be smaller.C. The mean and median would be smaller .D. The standard deviation and IQR would stay thesame.E. None of the above are correct.10. Which of the following is an example of a simple randomsample?A. Using a list of all pos si bl e participants, pick a ran-dom name in the list and then add a rand om numberto that pos it ion to find the next name, add anotherrandom number to find the next name, etc. untilyou have your sample.B. Using a list of all possible participants, pick a ran-dom name in the list, add a random number to thatposition to find th e next name, continue by addingthat same number until you have your sample.C. Throw all the names in a hat and draw out thedesired number of names.D. All of the above are examples of a simple r andomsample.E. None of the ab ove is an example of a simple randomsample.11. Suppose you’re buying long-st emme d roses for Valen-tine’s Day. The florist claims that the average lengthof her roses is 18 inches with a standard deviation of 2inches. If the distribution is actually approximately nor-mal, how likely are you to get a rose no longer than 12inches?A. 0.0013B. 0.0026C. 0.0087D. 0.0074E. You’re allergic to roses, so you go buy chocolatesinstead.12. The sample size n affectsA. whether the distribution is normal or not.B. whether the distribution (s ample ) is biased or not.C. whether we can use the 68-95-99.7% Rule or not.D. All of the above are true.E. None of the above are true.13. Describe the distribution above. ‘sd’ stands for standarddeviationA. shape = normal, center = 8, sd = 2B. shape = normal, center = 8, sd = 6C. shape = normal, center = 8, sd = 3D. shape = symmetric, center = 8, sd = 6E. shape = normal, center = 8, sd can’t be determined14. The LSAT (the
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