EE136 Presentation By Dan Lee Dec/6th/2003What is Soft Start? Why we need Soft Start?Soft Start 1PowerPoint PresentationStart and Soft StartSlide 6What is E.M.I.?Conducted Mode E.M.I.Example of In-Line FilterHow to prevent C.M. E.M.I. from the Switch section!C.M. E.M.I.How to Calculate Components!8Khz D.M. E.M.I.18Khz CutOff D.M. E.M.I.18Khz D.M. E.M.I. W/O L. Filters1.8Mhz CutOff D.M. E.M.I.C.M. E.M.I. 5Mhz, 30VoltC.M. E.M.I. 30V,5Mhz W/O L1 & L2 I=30V*w*C=18.8mAThank You!EE136 Presentation By Dan LeeDec/6th/2003Soft StartElectromagnetic InterferenceWhat is Soft Start?Why we need Soft Start?We want Converter to activate when proper voltage and current are set.We want Converter to start with narrow pulse width to prevent excess current from stressing components.Soft Start 1+-A1Q1D3C1R3R2E1+-A2R4R5R1E3+ VVM2Z200Vdc1D1E4SineREF3VDcD2N1S1Ctrl1.VAL+ VSine_1Vac_5Vdc+ VTriang5Vdc_1Vpp300Vdc line10Vdc lineR3.V [V] R5.V [V] R2.V [V] Triang5Vdc_1Vpp.V [V] Sine_1Vac_5Vdc.V [V] t [s] 0 0.2125m 50m 75m 0.1 0.13 0.15 0.18 0.2+-A1Q1D3C1R3R2E1+-A2R4R5R1E3+ VVM2Z200Vdc1D1E4SineREF3VDcD2N1S1Ctrl1.VAL+ VSine_1Vac_5Vdc+ VTriang5Vdc_1Vpp300Vdc line10Vdc lineStartStart and Soft StartR1C1Q2+-A1Z200VdcD1 D3D2D4C2R2R3R4R5R6R7R8R9C3C4D5D6D7D8D9Z9VQ1Sine120VacE2E3+ VSine5Vdc_1VppR10+ VTriang5Vdc_1VppS1S2TW TN_ratio_3300Vdc Line10Vdc LineR10.V [V] R8.V [V] Sine5Vdc_1Vpp.V [V] Triang5Vdc_1Vpp.V [V] R7.V [V] t [s] 12-202468100 0.3250m 0.1 0.15 0.2 0.25 0.3R1C1Q2+-A1Z200VdcD1 D3D2D4C2R2R3R4R5R6R7R8R9C3C4D5D6D7D8D9Z9VQ1Sine120VacE2E3+ VSine5Vdc_1VppR10+ VTriang5Vdc_1VppS1S2TWTN_ratio_3300Vdc Line10Vdc LineStart & Soft StartWhat is E.M.I.?Any unwanted conducted or radiated signals that affect the circuitry.It requires three conditions to have E.M.I. On the circuitry.1>Source2>receiver3>pathConducted Mode E.M.I.Differential or Serial Mode Interference.E.M.I. Between two LinesCommon Mode InterferenceThe E.M.I. Between a Line & GroundExample of In-Line FilterHow to prevent C.M. E.M.I. from the Switch section!C.M. E.M.I.Preventing C.M. E.M.I. Is better than suppressing it with filters.Once C.M. E.M.I. Is flows through ground, it can propagate to multitude paths.How to Calculate Components!Using Foster or Caur method isn’t recommended. Because of difficulty of finding Vo/Vin Transfer Function.CutOff Freq for C.M. is 18.5Khz.C.M. C2= Current / (2*Pi* Freq*Voltage)C.M. L1=1 / (C2*[4*Pi*Freq]^2)CutOff Freq for D.M. is 16Khz.D.M. L3=1/ (C4*[4*Pi*Freq]^2)C1L1L2L3L4C2C3C4E1E22m2m50u0.01u0.01u1u0.05u18k108Khz D.M. E.M.I.C4.V [V] C2.V [V] t [s] 0.13k-0.13k0-50500 40m5m 10m 15m 20m 25m 30m 35mC1L1L2L3L4C2C3C4E1E22m2m50u50u0.01u0.01u1u0.05u8k1018Khz CutOff D.M. E.M.I.C1L1L2L3L4C2C3C4E1E22m2m50u50u0.01u0.01u1u0.05u18k10C4.V [V] C2.V [V] t [s] 0.13k-0.13k0-50500 40m5m 10m 15m 20m 25m 30m 35m18Khz D.M. E.M.I. W/O L. FiltersC1C2C3C4E1E20.01u0.01u1u0.05u18k10C4.V [V] C2.V [V] t [s] 0.15k-0.15k0-0.1k-50500.1k0 20m2m 4m 6m 8m 10m 12m 14m 16m 18m1.8Mhz CutOff D.M. E.M.I.C4.V [V] C2.V [V] t [s] 0.13k-0.13k0-50500 40m5m 10m 15m 20m 25m 30m 35mC1L1L2L3L4C2C3C4E1E22m2m50u50u0.01u0.01u1u0.05u1800k70C.M. E.M.I. 5Mhz, 30VoltC1L1L2L3C2C3C4E1E210m10m50u50u0.01u0.01u1u0.05u4k5C520pI1C4.V [V] C2.V [V] t [s] 0.14k-20204060800.1k0 10m1m 2m 3m 4m 5m 6m 7m 8m 9mC.M. E.M.I. 30V,5Mhz W/O L1 & L2I=30V*w*C=18.8mAC4.V [V] C2.V [V] t [s] 0.14k-200204060800.1k0.12k0 10m1m 2m 3m 4m 5m 6m 7m 8m 9mC1L1L2L3L4C2C3C4E1E20050u50u0.01u0.01u1u0.05u4k5C520pI1Thank You!Any