Unformatted text preview:

COMPOSITE PATTERN AM DEMODULATIONUSING BANDPASS FILTERING AND ENVELOPE DETECTIONUpdated 9-16-05 LGHAssume you have Np modulated patterns for a My row by Nx column pattern image. Let Np =4, Nx=1024, My =768. Let =1 and kNp =92. For other frequencies let kn=(n-1) kNp/Np for n=1,2,… Np.If we let the PMP patterns be  pypmpnPMPNnMykyxs122cos,,and the Carrier patterns be xnncNxkyxs2cos,,then the modulated pattern is      yxsyxsyxsnPMPncn,1,,,,Figure 1: Sample of 2nd modulated pattern.The individual modulated patterns are combined by   pNnnPPCPyxsBAyxs1,,Where Ap and Bp are chose to map the values from 0 to 255.1Figure 2: Sample Composite Pattern.ANALYSIS AND VISUALIZATIONPerform a 2-D Discrete Fourier Transform (hint: use fft2 in MATLAB) on the composite pattern and point out the Np different channel signals in the DFT domain. Plot real, imaginary and magnitude spectra as an image. You can suppress the “dc” term by letting SCP[u,v]=0;    101022exp,,yxMyyxNxCPCPMvyjNuxjyxsvuSFigure 3: 2-Dimensional FFT of CP. The dc is zeroed out and the origin is shifted to the center ofthe image.Perform a 1-D DFT (Hint: use fft and perform on each row) on each row and plot, real, imaginary and magnitude of resulting matrix. Indicate where the channels are based on the magnitude image.2   102exp,,xNxxCPCPNuxjyxsyuSFigure 4: Partial DFT of the CP. Note the cosine amplitude is preserved in the vertical space direction.DEMODULATION OF Nth CHANNELBandpass filter that channel. For simplicity use a rectangular filter given by  xxnxxnnBPBNkurectBNkurectuH,3Figure 5: All four BandPass filters shown in 1-D format.where Bx/2 is half way between adjacent channels. Hint: negative frequencies wrap around so fork=0 is dc then if k<0, the computer index is knew=Nx-k. The intermediate result is     uHyuSyuGnBPCPnCP ,,,, Inverse DFT (hint: use ifft) back to the space domain such that   10,,2exp,1,xNuxnCPxnCPNuxjyuGNyxg4Figure 7: Bandpass filtered channel.and square such that   yxgyxfnCPnCP,,2,,Then DFT back to frequency domain and lowpass filter with a rectangular filter (hint: use irect) centered about the origin. The filter is given by LPxLPBurectuHwhere BLPx is equal to twice the value of the first carrier frequency k1. The response is     uHyuFyuRLPnCPnCP,,,,Square root the resulting envelope in the space domain to get the PMP estimate.   yxryxsnCPnPMP,,~,,5Figure 8: Demodulated channel.DEMODULATION OF ALL CHANNELSPerform these steps for all Np channels and show results.PHASE RETRIEVALWith all Np demodulated images, the phase is retrieved by     ppNnpnPMPNnpnPMPNnyxsNnyxsyx1,1,/)1(2cos,~/)1(2sin,~arctan,Plot the phase image.6Figure 9: Left is phase. By using a negative sine on one of the atan2(y,-x), parameters, the phase is shifted


View Full Document

UK EE 630 - Lecture Notes

Download Lecture Notes
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view Lecture Notes and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view Lecture Notes 2 2 and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?