DOC PREVIEW
Wright CHM 1210 - Practice exam_IV

This preview shows page 1-2 out of 7 pages.

Save
View full document
View full document
Premium Document
Do you want full access? Go Premium and unlock all 7 pages.
Access to all documents
Download any document
Ad free experience
View full document
Premium Document
Do you want full access? Go Premium and unlock all 7 pages.
Access to all documents
Download any document
Ad free experience
Premium Document
Do you want full access? Go Premium and unlock all 7 pages.
Access to all documents
Download any document
Ad free experience

Unformatted text preview:

Copyright Pearson Prentice Hall 1 Practice exam IV (100 points) + EC (8 points) CHM 1210, Department of Chemistry Some potentially useful equations and relationships, which will be provided to you during exam. 1 inch = 2.54 cm 12 inches = 1 ft 1 mile = 1.6093 km 1 gal = 3.7854 L 1 pound = 453.59 g 1 kg = 2.2046 pound 1 amu = 1.6605 x 10-24 g π = 3.14159 e- = 1.602 177  10–19 C e/m of the electron = 1.758 819  108 C/g for an electron m = 1.672 623  10–24 g for a proton and m = 1.674 927  10–24 g for a neutron Avogadro’s number: NA = 6.022 x 1023 formula units 22nkJ/mole 1312- = nc h R - = nE, where Rydberg constant: R = 1.097 x 10-2 nm-1 = 1.097 x 107 m-1 speed of light: c = 2.998 x 108 m s-1 Planck’s constant: h = 6.626 069 x 10-34 J s or (kg m2/s) Balmer-Rydberg equation: 22n1 - m1 R = 1 or 22n1 - m1 cR = with n > m de Broglie equation: λ = h /( m v) Heisenberg uncertainty principle:  4h (mv) x) (  Multiple Choice Questions, 108 Points (36 questions x 3 points/each question) 1. Arrange the following spectral regions in order of increasing wavelength: infrared, microwave, ultraviolet, visible. A) microwave < infrared < visible < ultraviolet B) microwave < visible < infrared < ultraviolet C) ultraviolet < infrared < visible < microwave D) ultraviolet < visible < microwave < infrared E) ultraviolet < visible < infrared < microwave 2. What is the frequency of a helium-neon laser light with a wavelength of 632.8 nm? A) 4.74 × 1014 s-1 B) 4.74 × 1020 s-1 C) 4.74 × 105 s-1 D) 2.11 × 10-15 s-1 E) 1.58 × 10-15 s-1 3. According to the Balmer-Rydberg equation, electromagnetic radiation with the shortest wavelength will be emitted when an electron undergoes which of the following transitions? A) m = 1 → n = 2 B) m = 2 → n = 3 C) n = 2 → m = 1 D) n = 3 → m = 2 E) none of the above 4. A person is most likely to experience serious biological effects when exposed to which of the following forms of electromagnetic radiation? A) Microwaves B) Infrared C) Ultraviolet D) Visible E) X-RaysCopyright Pearson Prentice Hall 2 5. Of the following, which has the shortest de Broglie wavelength? A) an airplane moving at a velocity of 300 mph B) a helium nucleus moving at a velocity of 1000 mph C) a helium nucleus moving at a velocity of 5000 mph D) a nitrogen molecule moving at a velocity of 1000 mph E) a nitrogen molecule moving at a velocity of 5000 mph 6. A baseball with a mass of 0.150 kg is moving at a velocity of 40 m/s (90 mph). If the uncertainity in the velocity is 0.1 m/s, the uncertainty in position A) may be zero B) must be less than or equal to 4 × 10-33 m C) must be 4 × 10-33 m D) must be greater than or equal to 4 × 10-33 m E) none of the above 7. Which of the following is true? A) The Bohr atom is the model currently accepted for electrons in atoms. B) Electrons travel around the nucleus in circular orbits. C) There is a 5% chance of finding an electron in an atom outside its orbital. D) The square of the wave function gives the probability of finding the electron. E) Each orbital is characterized by five quantum numbers. 8. How many subshells are there in the shell with n = 6? A) 1 B) 5 C) 6 D) 16 E) 36 9. Which of the following is not a valid set of quantum numbers? A) n = 2, l = 1, ml = 0, and ms = -1/2 B) n = 2, l = 1, ml = -1, and ms = -1/2 C) n = 3, l = 0, ml = 0, and ms = +1/2 D) n = 3, l = 2, ml = 3, and ms = +1/2 E) n = 4, l = 2, ml = 1, and ms = +1/2 10. An electron in a 4p orbital can have a wave function with which of the following set of quantum numbers, (n, l, ml, ms)? A) (4, 0, 0, 1/2) B) (4, 1, –1, –1/2) C) (5, 4, 1, +1/2) D) (5, 4, 1, –1/2) E) (5, 4, 4, 1/2) 11. Which orbitals do not have a node at the nucleus? A) s B) p C) all beyond the first shell D) all except for s E) none 12. Which of the following represent electron configurations that violate the Pauli exclusion principle? (i) [Ne]3s23p5 (ii) [Kr] 5s24d125p3 (iii) [Ar] 4s23d104p2 A) only (i) B) only (ii) C) only (iii) D) (i) and (ii) E) (ii) and (iii)Copyright Pearson Prentice Hall 3 13. For a multielectron atom, a 3s orbital lies lower in energy than a 3p orbital because A) a 3p orbital has more nodal surfaces than a 3s orbital B) other electrons more effectively shield electrons in the 3s orbital from the nucleus. C) other electrons more effectively shield electrons in the 3p orbital from the nucleus. D) there are more p orbitals than s orbitals in a given shell. E) all of the above. 14. What is the general valence-electron ground-state electron configuration for neutral alkaline earth metals? A) ns1 B) ns2 C) 1s22s1 D) 1s22s2 E) 1s22s22p1 15. What is the ground-state electron configuration of Co? A) [Ar]3d9 B) [Ar]4s13d8 C) [Ar]4s23d7 D) [Ar]4s24p64d1 E) [Ar]4s24p63d7 16. How many unpaired electrons are in an atom of Co in its ground state? A) 1 B) 2 C) 3 D) 6 E) 7 17. Give the quantum numbers (n, l, ml, ms) for the outer most electron (by filling order using the Aufbau Principle) in Co. A) 3, 2, -1, -1/2 B) 3, 1, -1, +1/2 C) 3, 1, -1, -1/2 D) 4, 1, 0, -1/2 E) 4, 1, 0, +1/2 18. What is the ground-state electron configuration of Co2+? A) [Ar] 4s23d5 B) [Ar]4s13d6 C) [Ar]4s03d7 D) [Ar]4s04p7 E) [Ar]4s23d5 19. For the fourth-shell orbital shown below, what are the principal quantum number, n, and the angular momentum quantum number, l? A) n = 4 and l = 0 B) n = 4 and l = 1 C) n = 4 and l = 2 D) n = 4 and l = 3 E) n = 4 and l = 4 20. The correct order of filling orbitals for ground state electronic configuration is (in order of increasing energy): A) 1s < 2s < 3s < 2p < 3p < 3d < 4s < 4p B) 1s < 2s < 2p < 3s < 3p < 4s < 4p < 3d C) 1s < 2s < 2p < 3s < 3p < 3d < 4s < 4p D) 1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p E) none of the aboveCopyright …


View Full Document

Wright CHM 1210 - Practice exam_IV

Download Practice exam_IV
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view Practice exam_IV and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view Practice exam_IV 2 2 and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?