DOC PREVIEW
Berkeley MATH 54 - Inner products

This preview shows page 1 out of 3 pages.

Save
View full document
View full document
Premium Document
Do you want full access? Go Premium and unlock all 3 pages.
Access to all documents
Download any document
Ad free experience
Premium Document
Do you want full access? Go Premium and unlock all 3 pages.
Access to all documents
Download any document
Ad free experience

Unformatted text preview:

Inner productsOctober 8, 2007Inner products are used to deal with two important geometric notions:angle and distance.Definition 1 Let v and w be vectors in Rn, with coordinates (x1, . . . xn)and (y1, . . . yn), respectively. Then the inner product or dot product of v andw is:v · w := hv, wi := (v|w) := x1y1+ x2y2+ · · · xnyn.Note that there are at least three sets of notation commonly used to denotethe inner product. Furthermore, it is sometimes called the “dot product” or“scalar product.” Note that the dot product of two vectors in Rnis a realnumber, and that the matrix product vTw is the 1 × 1 matrix whose onlyentry is (v|w). We shall sometimes identify the matrix vTw with the number(v|w).Theorem 2 The inner produc t Rn× Rn→ R satisfies the following prop-erties:1. (v + v0|w) = (v|w) + (v0|w) if v, v0, w ∈ Rn.2. (av|w) = a(v|w) if v, w ∈ Rnand a ∈ R.3. (v|w) = (w|v) if v, w ∈ Rn.4. (v|v) > 0 if v 6= 0, for any v ∈ Rnand (0|0) = 0.These properties are quite easy to verify. Note however that the last of themuses the special fact that the square of any real number is positive.1Definition 3 If v ∈ Rn, then ||v|| :=q(v|v). The (nonnegative) real num-ber ||v|| is called the magnitude or length of v. If v and w are two elementsRn, then ||v − w|| is called the distance between v and w. If v, w ∈ Rn, thenv ⊥ w if (v|w) = 0, in which case we say that v and w are orthogonal.Proposition 4 If v, w ∈ Rn, then1. ||v + w||2= ||v||2+ ||w||2+ 2(v|w).2. If v ⊥ w, then ||v + w||2= ||v||2+ ||w||2.3. |(v|w)| ≤ ||v|| ||w||.4. ||v + w|| ≤ ||v|| + ||w||.Of these, the only difficult one is (3), the Cauchy-Schwartz ine quality. It iseasy to prove (4) from (3) and (1).Definition 5 A sequence of vectors (v1, . . . vm) in Rnis orthogonal if vi⊥ vjwhenever i 6= j. The sequence is orthonormal if it is orthogonal and inaddition ||vi|| = 1 for all i.The following result is probably the most important theorem about innerproducts.Theorem 6 Let W be a linear subspace of Rnand let v be a member ofRn. There v can be written uniquelyv = πW(v) + π⊥W(v),where πW(v) ∈ W and π⊥W(v) is orthogonal to every vector in W . Further-more:1. πW(v) is the vector in W which is closest to v. That is,||πW(v) − v|| ≤ ||w − v|| for every w ∈ W ,with equality only if w = πW(v).2. If (w1, . . . wm) is an orthonormal basis for W , thenπW(v) = (v|w1)w1+ · · · (v|wm)wm.23. More generally, if (w1, . . . wm) if an orthogonal basis for W , thenπW(v) =(v|w1)w1||w1||2+ · · ·(v|wm)wm||wm||2.Let me explain a proof of (1). Let w0:= πW(v) This a vector in W . Let w beany other vector in W . We claim that if w 6= w0, then ||v − w|| > ||v − w0||.Let w0:= w0− w. This is another vector in W , and||v − w||2= ||(v − w0) + (w0− w)||2= ||π⊥(v) + w0||2= ||π⊥(v)||2+ ||w0||2since π⊥(v) is orthogonal to w0(use formula ). But ||w0||2≥ 0, and is zeroonly if w =


View Full Document

Berkeley MATH 54 - Inner products

Download Inner products
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view Inner products and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view Inner products 2 2 and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?