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DePaul HON 225 - Measurements and Unit Conversions

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HON 225 Graded Homework (50 points) Measurements and Unit Conversions Carefully read the handout on Significant Figures and Units/Conversion of Units, then complete the following. I. SIGNIFICANT FIGURES 1. (5 pts) State the number of significant figures in the following values: a. 39.44 m 4 b. 95° 2 c. 1.008 g 4 d. 0.0005 in 1 e. 1.55 x 108 3 2. (5 pts) Calculate the problems and give final answers to the proper number of significant figures, expressed using scientific notation. a. 2.5 x 7 2 x 101 b. 6.354/0.52 1.2 x 101 c. (4.2 x 108)/(2.17 x 104) 1.9 x 104 d. (5.85 x 103) + (4.001 x 105) 4.059 x 105 or 4.060 x 105 e. (4 x 107) x (3 x 106) 1 x 1014 II. ROUNDING OFF (4 pts) Round the following numbers to the indicated precision ("place" means significant digit): a. 5653, three places 5650 b. 0.7921, one place 0.8 c. 5.57, two places 5.6 d. 850, one place 800 or 900 III. SCIENTIFIC NOTATION 1. (5 pts) Put the following values in scientific notation. Assume zeros preceding the decimal point are not significant. a. 300,000 3 x 105 b. 465,000,000 4.65 x 108 c. 0.0005 5 x 10–4 d. 0.00716 7.16 x 10–3 e. 293 2.93 x 102 2. (3 pts) Convert the following values (already in scientific notation) to normal form: a. 2.19 x 104 21900 b. 6.8 x 103 6800 c. 3 x 10-6 0.0000032 IV. CONVERSIONS (Show your work) 1. (6 pts) Convert 3 x 108 km/s to km/year. (3 x 108 km/s) (3600 s/hr) (24 hr/day) (365.25 day/yr) = 9 x 1015 km/yr 2. (6 pts) The planet Pluto has a mean distance from the sun of 39 AU. Convert this to km (1 AU = 1.55 x 108 km). (39 AU) (1.55 x 108 km/AU) = 6.0 x 109 km For the following two problems, assume zeros preceding decimal points are not significant. 3. (6 pts) Find the ratio of the distance of the Moon from the Earth to the Moon’s diameter (Moon's average distance = 384,400 km, Moon's diameter = 3476 km). 384,400 km/3476 km = 110.6 4. (6 pts) The Earth is nearly 8000 mi in diameter. Jupiter is much larger, having a diameter of 144,800 km. Since 1 mi = 1.61 km, how many times larger is Jupiter’s diameter than Earth’s? Need both Earth and Jupiter to have the same units: Earth: (8000 mi) (1.61 km/mi) = 1.288 x 104 The sig figs wrong for this intermediate step; final answer will be rounded correctly). Since Earth is “nearly” 8000 mi in diameter, this value is approximate and has just one sig fig. Ratio = 144,800 km/1.288 x 104 km = 11.24 ~ 10 (to one sig fig) V. MEASUREMENTS What is wrong with the following measurements? a. (2 pts) 0.935 x 106 m not proper scientific notation b. (2 pts) 5.75 no


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